AC Capacitance
A capacitor consists basically of two very close together metal or conductive plates separated by an
insulating layer called the dielectric as we saw in our tutorials about
Capacitors. The purpose of a capacitor is
to store energy in the form of an electrical charge, Q on its plates. When a capacitor is connected
across a DC supply voltage it charges up to the value of the applied voltage at a rate determined by its time constant and
will maintain or hold this charge indefinitely as long as the supply voltage is present. During this charging process, a
charging current, i flows into the capacitor opposed by any changes to the voltage at a rate
which is equal to the rate of change of the electrical charge on the plates. A capacitor therefore has an opposition to
current flowing through it.
The relationship between this charging current and the rate at which the capacitors supply voltage
changes can be defined mathematically as: i = C(dV/dt), where C is
the capacitance value of the capacitor in farads and dV/dt is the rate of change of the supply
voltage with respect to time. Once it is "fully-charged" the capacitor blocks the flow of any more electrons onto its
plates as they have become saturated and the capacitor now acts like a temporary storage device.
A pure capacitor will maintain this charge indefinitely on its plates even if the DC supply voltage
is removed. However, in a sinusoidal voltage circuit which contains "AC Capacitance", the capacitor will alternately charge
and discharge at a rate determined by the frequency of the supply. Then capacitors in AC circuits are constantly charging
and discharging respectively.
When an alternating sinusoidal voltage is applied to the plates of a capacitor, the capacitor is charged
firstly in one direction and then in the opposite direction changing polarity at the same rate as the AC supply voltage.
This instantaneous change in voltage across the capacitor is opposed by the fact that it takes a certain amount of time to
deposit (or release) this charge onto the plates and is given by V = Q/C.
Consider the circuit below.
AC Capacitance with a Sinusoidal Supply
When the switch is closed in the circuit above, a high current will start to flow into the capacitor as there is no charge on the plates at t = 0. The sinusoidal supply voltage, V is increasing in a positive direction at its maximum rate as it crosses the zero reference axis at an instant in time given as 0o. Since the rate of change of the potential difference across the plates is now at its maximum value, the flow of current through the capacitor will also be at its maximum rate as the maximum amount of electrons are moving from one plate to the other.
As the sinusoidal supply voltage reaches its 90o point on the
waveform it begins to slow down and for a very brief instant in time the potential difference across the plates is neither
increasing nor decreasing therefore the current decreases to zero as there is no rate of voltage change. At this
90o point the potential difference across the capacitor is at its maximum
( Vmax ), no current flows into the capacitor as the capacitor is now fully charged.
At the end of this instant in time the supply voltage begins to decrease in a negative direction down towards
the zero reference line at 180o.
Although the supply voltage is still positive in nature the
capacitor starts to discharge some of its excess electrons on its plates
in an effort to maintain a constant voltage. This results
in the capacitor current flowing in the opposite or negative direction.
When the supply voltage waveform crosses the zero reference axis point at instant 180o,
the rate of change or slope of the sinusoidal supply voltage is at its maximum but in a negative direction, consequently
the current flowing through the capacitor is also at its maximum rate at that instant. Also at this 180o
point the potential difference across the plates is zero as the amount of charge is equally distributed between the two plates.
Then during this first half cycle 0o to 180o, the applied
voltage reaches its maximum positive value a quarter (1/4ƒ) of a cycle after the current reaches its maximum positive value,
in other words, a voltage applied to a purely capacitive circuit "LAGS" the current by a quarter of a cycle or 90o as shown below.
Sinusoidal Waveforms for AC Capacitance
During the second half cycle 180o to 360o, the supply voltage
reverses direction and heads towards its negative peak value at 270o. At this point the
potential difference across the plates is neither decreasing nor increasing and the current decreases to zero. The potential
difference across the capacitor is at its maximum negative value, no current flows into the capacitor and it becomes fully
charged the same as at its 90o point but in the opposite direction.
As the negative supply voltage begins to increase in a positive direction towards the
360o point on the zero reference line, the fully charged capacitor must now loose some
of its excess electrons to maintain a constant voltage as before and starts to discharge itself until the supply voltage
reaches zero at 360o at which the process of charging and discharging starts over again.
From the voltage and current waveforms and description above, we can see that the current is always leading
the voltage by 1/4 of a cycle or π/2 = 90o "out-of-phase" with the
potential difference across the capacitor because of this charging and discharging process. Then the phase relationship
between the voltage and current in an AC capacitance circuit is the exact opposite to that of an
AC Inductance we saw in the previous tutorial.
This effect can also be represented by a phasor diagram where in a purely capacitive circuit the voltage "LAGS"
the current by 90o. But by using the voltage as our reference, we can also say that the current "LEADS" the voltage by
one quarter of a cycle or 90o as shown in the vector diagram below.
Phasor Diagram for AC Capacitance
So for a pure capacitor, VC "lags" IC by
90o, or we can say that IC "leads" VC by 90o.
There are many different ways to remember the phase relationship between the voltage and current flowing through a
pure AC capacitance circuit, but one very simple and easy to remember way is to use the mnemonic expression called "ICE".
ICE stands for current I first in an AC capacitance, C
before Electromotive force. In other words, current before the voltage in a capacitor, I,
C, E equals "ICE", and whichever phase angle the voltage
starts at, this expression always holds true for a pure AC capacitance circuit.
Capacitive Reactance
So we now know that capacitors oppose changes in
voltage with the flow of electrons through the capacitor being
directly proportional to the rate of voltage change across its plates as
the capacitor charges and discharges. Unlike a resistor
where the opposition to current flow is its actual resistance, the
opposition to current flow in a capacitor is called
Reactance. Like resistance, reactance is measured in Ohm's but is given the symbol X to
distinguish it from a purely resistive R value and as the component in question is a capacitor, the
reactance of a capacitor is called Capacitive Reactance, ( XC )
which is measured in Ohms.
Since capacitors pass current through themselves in
proportion to the rate of voltage change, the faster the
voltage changes the more current they will pass. Likewise, the slower
the voltage changes the less current they will pass. This means
then that the reactance of a capacitor is "inversely proportional" to
the frequency of the supply as shown.
Capacitive Reactance
Where: XC is the Capacitive Reactance in Ohms, ƒ is the
frequency in Hertz and C is the capacitance in Farads, symbol F.
We can also define capacitive reactance in terms of radians, where Omega, ω equals 2πƒ.
From the above formula we can see that the value of capacitive reactance and therefore its overall impedance ( in Ohms ) decreases towards zero as the frequency increases acting like a short circuit. Likewise, as the frequency approaches zero or DC, the capacitors reactance increases to infinity, acting like an open circuit which is why capacitors block DC.
The relationship between capacitive reactance and frequency is the exact opposite to that of inductive
reactance, ( XL ) we saw in the previous tutorial. This means then that
capacitive reactance is "inversely proportional to frequency" and has a high value at low frequencies and a low value at
higher frequencies as shown.
Capacitive Reactance against Frequency
Capacitive reactance of a capacitor decreases as the frequency across its plates
increases. Therefore, capacitive reactance is inversely proportional to frequency. Capacitive reactance opposes current flow
but the electrostatic charge on the plates (its AC capacitance value) remains constant.
This means it becomes easier for the capacitor to fully absorb the change in charge on its plates during each half cycle. Also as the frequency increases the current flowing through the capacitor increases in value because the rate of voltage change across its plates increases. |
We can present the effect of very low and very high frequencies on the reactance of a pure AC Capacitance as follows:
In an AC circuit containing pure capacitance the current flowing through the capacitor is given as:
and therefore, the rms current flowing through an AC capacitance will be defined as:
Where: IC = V/(ωC) which is the current
amplitude and θ = + 90o which is the phase
difference or phase angle between the voltage and current. For a purely capacitive circuit, Ic leads
Vc by 90o, or Vc lags Ic by 90o.
Phasor Domain
In the phasor domain the voltage across the plates of an AC capacitance will be:
and in Polar Form this
would be written as: XC∠-90o where:
AC through a Series R + C Circuit
We have seen from above that the current flowing through a pure capacitance leads the voltage by
90o. But in the real world, it is impossible to have a pure AC Capacitance
as all capacitors will have a certain amount of internal resistance across their plates giving rise to a leakage current. Then
we can consider our capacitor as being one that has a resistance, R in series with a capacitance,
C producing what can be loosely called an "impure capacitor".
If the capacitor has some "internal" resistance then we need to represent the total impedance of the capacitor
as a resistance in series with a capacitance and in an AC circuit that contains both capacitance, C
and resistance, R the voltage phasor, V across the combination will be
equal to the phasor sum of the two component voltages, VR and VC.
This means then that the current flowing through the capacitor will still lead the voltage, but by an amount less than 90o
depending upon the values of R and C giving us a phasor
sum with the corresponding phase angle between them given by the Greek symbol phi, Φ.
Consider the circuit below where an ohmic resistance, R is connected in
series with a pure capacitance, C.
Series Resistance-Capacitance Circuit
In the RC series circuit above, we can see that the current flowing through the circuit is common to both the resistance and capacitance, while the voltage is made up of the two component voltages, VR and VC. The resulting voltage of these two components can be found mathematically but since vectors VR and VC are 90o out-of-phase, they can be added vectorially by constructing a vector diagram.
To be able to produce a vector diagram for a
capacitance a reference or common component must be found.
In a series AC circuit the current is common and can therefore be used
as the reference source because the same current flows
through the resistance and capacitance. The individual vector diagrams
for a pure resistance and a pure capacitance are given as:
Vector Diagrams for the Two Pure Components
Both the voltage and current vectors for an
AC Resistance are in phase with
each other and therefore the voltage vector VR is drawn superimposed to scale onto the current
vector. Also we know that the current leads the voltage ( ICE ) in a pure AC capacitance circuit, therefore the voltage
vector VC is drawn 90o behind ( lagging ) the current vector and to the
same scale as VR as shown.
Vector Diagram of the Resultant Voltage
In the vector diagram above, line OB represents the horizontal current reference
and line OA is the voltage across the resistive component which is in-phase with the current. Line
OC shows the capacitive voltage which is 90o behind the current therefore it can still be
seen that the current leads the purely capacitive voltage by 90o. Line OD gives us the resulting
supply voltage.
As the current leads the voltage in a pure capacitance by 90o the resultant phasor diagram drawn
from the individual voltage drops VR and VC represents a
right angled voltage triangle shown above as OAD. Then we can also use Pythagoras's theorem to mathematically
find the value of this resultant voltage across the resistor/capacitor ( RC ) circuit.
As VR = I.R and VC = I.XC
the applied voltage will be the vector sum of the two as follows.
The quantity
represents the impedance, Z of the circuit.
The Impedance of an AC Capacitance
Impedance, Z which has the units of Ohms, Ω's is the "TOTAL"
opposition to current flowing in an AC circuit that contains both Resistance, ( the real part ) and Reactance
( the imaginary part ). A purely resistive impedance will have a phase angle of 0o while a purely
capacitive impedance will have a phase angle of -90o.
However when resistors and capacitors are connected together in the same circuit, the total impedance
will have a phase angle somewhere between 0o and 90o depending upon the value of the components used.
Then the impedance of our simple RC circuit shown above can be found by using the impedance triangle.
The RC Impedance Triangle
Then: ( Impedance )2 = ( Resistance )2 + ( j Reactance )2 where j represents the 90o phase shift.
This means then by using Pythagoras's theorem the negative phase angle, θ between the voltage and current is calculated as.
Phase Angle
Example No1
A single-phase sinusoidal AC supply voltage defined as:
V(t) = 240 sin(314t - 20o)
is connected to a pure AC capacitance of 200uF. Determine the value of the current flowing through the capacitor
and draw the resulting phasor diagram.
The voltage across the capacitor will be the same as the supply voltage. Converting this time domain value into
polar form gives us: VC = 240 ∠-20o (v). The capacitive
reactance will be: XC = 1/( ω.200uF ).
Then the current flowing through the capacitor can be found using Ohms law as:
With the current leading the voltage by 90o in an AC capacitance circuit the phasor diagram will be.
Example No2
A capacitor which has an internal resistance of 10Ω's and a capacitance value of 100uF is
connected to a supply voltage given as V(t) = 100 sin (314t).
Calculate the current flowing through the capacitor. Also construct a voltage triangle showing the individual voltage drops.
The capacitive reactance and circuit impedance is calculated as:
Then the current flowing through the capacitor and the circuit is given as:
The phase angle between the current and voltage is calculated from the impedance triangle above as:
Then the individual voltage drops around the circuit are calculated as:
Then the resultant voltage triangle will be.
AC Capacitance Summary
In a pure AC Capacitance circuit, the voltage and current are both "out-of-phase"
with the current leading the voltage by 90o and we can remember this by using the mnemonic expression
"ICE". The AC resistive value of a capacitor called impedance, ( Z ) is related
to frequency with the reactive value of a capacitor called "capacitive reactance", XC.
In an AC Capacitance circuit, this capacitive reactance value is equal to 1/( 2πƒC )
or 1/( jωC )
Thus far we have seen that the relationship between voltage and current is not the same and changes
in all three pure passive components. In the Resistance the phase angle is 0o, in the Inductance
it is +90o while in the Capacitance it is -90o. In the next tutorial about
Series RLC Circuits we will
look at the voltage-current relationship of all three of these passive components when connected together in the same
series circuit when a steady state sinusoidal AC waveform is applied along with the corresponding phasor diagram
representation.
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